1
0
Fork 0
arangodb/lib/Basics/levenshtein.cpp

99 lines
3.1 KiB
C++

#include "levenshtein.h"
////////////////////////////////////////////////////////////////////////////////
/// @brief calculate the levenshtein distance of the two strings
///
/// This function implements the Damerau-Levenshtein algorithm to
/// calculate a distance between strings.
///
/// Basically, it says how many letters need to be swapped, substituted,
/// deleted from, or added to string1, at least, to get string2.
///
/// The idea is to build a distance matrix for the substrings of both
/// strings. To avoid a large space complexity, only the last three rows
/// are kept in memory (if swaps had the same or higher cost as one deletion
/// plus one insertion, only two rows would be needed).
///
/// At any stage, "i + 1" denotes the length of the current substring of
/// string1 that the distance is calculated for.
///
/// row2 holds the current row, row1 the previous row (i.e. for the substring
/// of string1 of length "i"), and row0 the row before that.
///
/// In other words, at the start of the big loop, row2[j + 1] contains the
/// Damerau-Levenshtein distance between the substring of string1 of length
/// "i" and the substring of string2 of length "j + 1".
///
/// All the big loop does is determine the partial minimum-cost paths.
///
/// It does so by calculating the costs of the path ending in characters
/// i (in string1) and j (in string2), respectively, given that the last
/// operation is a substitution, a swap, a deletion, or an insertion.
///
/// This implementation allows the costs to be weighted:
///
/// - w (as in "sWap")
/// - s (as in "Substitution")
/// - a (for insertion, AKA "Add")
/// - d (as in "Deletion")
///
/// Note that this algorithm calculates a distance _iff_ d == a.
///
/// @author https://github.com/git/git/blob/master/levenshtein.c
////////////////////////////////////////////////////////////////////////////////
int TRI_Levenshtein (char const* string1,
char const* string2,
int w,
int s,
int a,
int d) {
int len1 = static_cast<int>(strlen(string1));
int len2 = static_cast<int>(strlen(string2));
int* row0 = new int[len2 + 1];
int* row1 = new int[len2 + 1];
int* row2 = new int[len2 + 1];
for (int j = 0; j <= len2; j++) {
row1[j] = j * a;
}
int i;
for (i = 0; i < len1; i++) {
int *dummy;
row2[0] = (i + 1) * d;
for (int j = 0; j < len2; j++) {
/* substitution */
row2[j + 1] = row1[j] + s * (string1[i] != string2[j]);
/* swap */
if (i > 0 && j > 0 && string1[i - 1] == string2[j] &&
string1[i] == string2[j - 1] &&
row2[j + 1] > row0[j - 1] + w) {
row2[j + 1] = row0[j - 1] + w;
}
/* deletion */
if (row2[j + 1] > row1[j + 1] + d) {
row2[j + 1] = row1[j + 1] + d;
}
/* insertion */
if (row2[j + 1] > row2[j] + a) {
row2[j + 1] = row2[j] + a;
}
}
dummy = row0;
row0 = row1;
row1 = row2;
row2 = dummy;
}
i = row1[len2];
delete[] row0;
delete[] row1;
delete[] row2;
return i;
}