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@Q:
FOR v, e, p IN <span class="hljs-number">1.</span><span class="hljs-number">.3</span> OUTBOUND <span class="hljs-string">'circles/A'</span> GRAPH <span class="hljs-string">'traversalGraph'</span>
FILTER p.edges[<span class="hljs-number">0</span>].label != <span class="hljs-string">'right_foo'</span>
RETURN v._key
@R
[
<span class="hljs-string">"B"</span>,
<span class="hljs-string">"C"</span>,
<span class="hljs-string">"D"</span>,
<span class="hljs-string">"E"</span>,
<span class="hljs-string">"F"</span>
]