Array Operators =============== Array expansion --------------- In order to access a named attribute from all elements in an array easily, AQL offers the shortcut operator [\*] for array variable expansion. Using the [\*] operator with an array variable will iterate over all elements in the array, thus allowing to access a particular attribute of each element. It is required that the expanded variable is an array. The result of the [\*] operator is again an array. To demonstrate the array expansion operator, let's go on with the following three example *users* documents: ```json [ { name: "john", age: 35, friends: [ { name: "tina", age: 43 }, { name: "helga", age: 52 }, { name: "alfred", age: 34 } ] }, { name: "yves", age: 24, friends: [ { name: "sergei", age: 27 }, { name: "tiffany", age: 25 } ] }, { name: "sandra", age: 40, friends: [ { name: "bob", age: 32 }, { name: "elena", age: 48 } ] } ] ``` With the [\*] operator it becomes easy to query just the names of the friends for each user: ``` FOR u IN users RETURN { name: u.name, friends: u.friends[*].name } ``` This will produce: ```json [ { "name" : "john", "friends" : [ "tina", "helga", "alfred" ] }, { "name" : "yves", "friends" : [ "sergei", "tiffany" ] }, { "name" : "sandra", "friends" : [ "bob", "elena" ] } ] ``` This is a shortcut for the longer, semantically equivalent query: ```js FOR u IN users RETURN { name: u.name, friends: (FOR f IN u.friends RETURN f.name) } ``` Array contraction ----------------- In order to collapse (or flatten) results in nested arrays, AQL provides the [\*\*] operator. It works similar to the [\*] operator, but additionally collapses nested arrays. How many levels are collapsed is determined by the amount of asterisk characters used. [\*\*] collapses one level of nesting - just like `FLATTEN(array)` or `FLATTEN(array, 1)` would do -, [\*\*\*] collapses two levels - the equivalent to `FLATTEN(array, 2)` - and so on. Let's compare the array expansion operator with an array contraction operator. For example, the following query produces an array of friend names per user: ```js FOR u IN users RETURN u.friends[*].name ``` As we have multiple users, the overall result is a nested array: ```json [ [ "tina", "helga", "alfred" ], [ "sergei", "tiffany" ], [ "bob", "elena" ] ] ``` If the goal is to get rid of the nested array, we can apply the [\*\*] operator on the result. But simply appending [\*\*] to the query won't help, because *u.friends* is not a nested (multi-dimensional) array, but a simple (one-dimensional) array. Still, the [\*\*] can be used if it has access to a multi-dimensional nested result. We can extend above query as follows and still create the same nested result: ```js RETURN ( FOR u IN users RETURN u.friends[*].name ) ``` By now appending the [\*\*] operator at the end of the query... ```js RETURN ( FOR u IN users RETURN u.friends[*].name )[**] ``` ... the query result becomes: ```json [ [ "tina", "helga", "alfred", "sergei", "tiffany", "bob", "elena" ] ] ``` Note that the elements are not de-duplicated. For a flat array with only unique elements, a combination of [UNIQUE()](../Functions/Array.md#unique) and [FLATTEN()](../Functions/Array.md#flatten) is advisable. Inline expressions ------------------ It is possible to filter elements while iterating over an array, to limit the amount of returned elements and to create a projection using the current array element. Sorting is not supported by this shorthand form. These inline expressions can follow array expansion and contraction operators [\* ...], [\*\* ...] etc. The keywords *FILTER*, *LIMIT* and *RETURN* must occur in this order if they are used in combination, and can only occur once: `anyArray[* FILTER conditions LIMIT skip,limit RETURN projection]` Example with nested numbers and array contraction: ```js LET arr = [ [ 1, 2 ], 3, [ 4, 5 ], 6 ] RETURN arr[** FILTER CURRENT % 2 == 0] ``` All even numbers are returned in a flat array: ```json [ [ 2, 4, 6 ] ] ``` Complex example with multiple conditions, limit and projection: ```js FOR u IN users RETURN { name: u.name, friends: u.friends[* FILTER CONTAINS(CURRENT.name, "a") AND CURRENT.age > 40 LIMIT 2 RETURN CONCAT(CURRENT.name, " is ", CURRENT.age) ] } ``` No more than two computed strings based on *friends* with an `a` in their name and older than 40 years are returned per user: ```json [ { "name": "john", "friends": [ "tina is 43", "helga is 52" ] }, { "name": "sandra", "friends": [ "elena is 48" ] }, { "name": "yves", "friends": [] } ] ``` ### Inline filter To return only the names of friends that have an *age* value higher than the user herself, an inline *FILTER* can be used: ```js FOR u IN users RETURN { name: u.name, friends: u.friends[* FILTER CURRENT.age > u.age].name } ``` The pseudo-variable *CURRENT* can be used to access the current array element. The *FILTER* condition can refer to *CURRENT* or any variables valid in the outer scope. ### Inline limit The number of elements returned can be restricted with *LIMIT*. It works the same as the [limit operation](../Operations/Limit.md). *LIMIT* must come after *FILTER* and before *RETURN*, if they are present. ```js FOR u IN users RETURN { name: u.name, friends: u.friends[* LIMIT 1].name } ``` Above example returns one friend each: ```json [ { "name": "john", "friends": [ "tina" ] }, { "name": "sandra", "friends": [ "bob" ] }, { "name": "yves", "friends": [ "sergei" ] } ] ``` A number of elements can also be skipped and up to *n* returned: ```js FOR u IN users RETURN { name: u.name, friends: u.friends[* LIMIT 1,2].name } ``` The example query skips the first friend and returns two friends at most per user: ```json [ { "name": "john", "friends": [ "helga", "alfred" ] }, { "name": "sandra", "friends": [ "elena" ] }, { "name": "yves", "friends": [ "tiffany" ] } ] ``` ### Inline projection To return a projection of the current element, use *RETURN*. If a *FILTER* is also present, *RETURN* must come later. ```js FOR u IN users RETURN u.friends[* RETURN CONCAT(CURRENT.name, " is a friend of ", u.name)] ``` The above will return: ```json [ [ "tina is a friend of john", "helga is a friend of john", "alfred is a friend of john" ], [ "sergei is a friend of yves", "tiffany is a friend of yves" ], [ "bob is a friend of sandra", "elena is a friend of sandra" ] ] ```